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How to assign input file name to a variable dynamically in python recipe

NilamberPanda
Level 2
Level 2
How to assign input file name to a variable dynamically in python recipe

Hi, 

I am creating a flow where a User will upload csv files everytime they use my flow. I want to dynamically store this filename in a variable and use in my python code. How can I store the filename dynamically in a variable ?


Operating system used: Windows

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1 Reply
fchataigner2
Dataiker
Dataiker

Hi,

if "upload" in this context means "upload in a UploadedFiles dataset", then you can get the names of the files in such a dataset with a few lines of python

import dataiku
ds = dataiku.Dataset('the_name_of_the_dataset')
file_paths = [p['path'] for p in ds.get_files_info()['globalPaths']]

and file_paths will be the '/'-prefixed list of names of files in the dataset 

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