Keyword for creating sql spark recipe via Python API

[nmadhu20]

Hi Team, 

Could you please help me clear below doubts?

The use-case here is that the output of window recipe(s3) would be input to sql-spark recipe whose query we will dynamically create in python, add and run it from python. The output will also be s3 output.

builder = project.new_recipe(??) #what would be the keyword for sql_spark?
builder.with_input(output_df)
builder.with_new_output("name_of_output_dataset", "s3_connection_name")
recipe = builder.create()

recipe_settings.get_json_payload() #for adding  query in the recipe which keyword is used?

ThankYou in advance.

[AlexandreL · Accepted solution]

Hello,

Can you explain a bit more why you need to create a sparksql recipe programmatically ? Having to create such recipes is not easy so there might be another simpler way to solve your issue. Anyway, you can do it but not from the new_recipe method. You'll need to use the create_recipe method. Which is harder to use. You can use the following code. If you need to find which values to use for specific parameters, such as a dataset's storage format for example, feel free to create such object via the UI, and then copy its settings.

%pylab inline

import dataiku
from dataiku import pandasutils as pdu
import pandas as pd

#Instanciate client
client = dataiku.api_client()

project = client.get_project("PROJECT_KEY")
output_dataset_name = "output_dataset_name"
input_dataset_name = "input_dataset_name"
output_dataset_connection = 'connection_name'
recipe_name = "compute_" + output_dataset_name

#First, output dataset needs to be created
project.create_dataset(output_dataset_name, formatType="csv", params={'connection': output_dataset_connection,
  'filesSelectionRules': {'excludeRules': [],
   'explicitFiles': [],
   'includeRules': [],
   'mode': 'ALL'}}, type="HDFS")

#Then, we can create the recipe
recipe_proto = {}
recipe_proto["type"] = "spark_sql_query"
recipe_proto["name"] = recipe_name
recipe_proto["inputs"] = {'main': {'items': [{'appendMode': False,
     'ref': input_dataset_name}]}}
recipe_proto["outputs"] = {'main': {'items': [{'appendMode': False,
     'ref': output_dataset_name}]}}

creation_settings = {
    "useGlobalMetastore": False,
    "useGlobalMetastore": True,
    "forcePipelineableForTests": False,  
}

spsql_recipe = project.create_recipe(recipe_proto, creation_settings)

# Finally, modify the recipe's code
recipe_def = spsql_recipe.get_definition_and_payload()
recipe_def.set_payload("YOUR SQL CODE HERE")
spsql_recipe.set_definition_and_payload(recipe_def)

[nmadhu20]

Thanks for your reply.

I created a sql recipe instead of sql spark and yes it was much more straight forward and easier.