How to write this formula in dataiku ?
prash_
Registered Posts: 17 ✭
IF [ASIA]=0 THEN "CERO"
ELSEIF [ASIA]<=1 THEN
IF [ASIA]>=-1 THEN "DENTRLRANCIA"
ELSEIF [ASIA]>0 THEN "DIFERETIVA"
ELSE "DIFERENTIVA" ENDIF
ELSEIF [TOTAL]=0 THEN "DIOT"
ELSEIF [TOTAL_CONTABLE]=0 THEN "CONTABLE"
ELSEIF [ASIA]>0 THEN "DIFER POSI"
ELSE "DIFERNEGVA" ENDIF
Answers
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Alexandru Dataiker, Dataiku DSS Core Designer, Dataiku DSS ML Practitioner, Dataiku DSS Adv Designer, Registered Posts: 1,226 Dataiker
Hi @prash_
,
You can use :https://doc.dataiku.com/dss/latest/preparation/processors/create-if-then-else.html
Or use nested IFs in formula: "if(condition, true, if(condition, true, false))" to do nested if/else if.
If the complexity it high to handle you can use Python Function in prepare recipe instead.
https://knowledge.dataiku.com/latest/data-preparation/prepare-recipe/reference-prepare-recipe-python-step.htmldef process(row): ASIA = row['ASIA'] # Replace 'ASIA' with the actual column name for Asia values TOTAL = row['TOTAL'] # Replace 'TOTAL' with the actual column name for Total values TOTAL_CONTABLE = row['TOTAL_CONTABLE'] # Replace 'TOTAL_CONTABLE' with the actual column name for Total Contable values if ASIA == 0: return "CERO" elif ASIA <= 1: if ASIA >= -1: return "DENTRLRANCIA" elif ASIA > 0: return "DIFERETIVA" else: return "DIFERENTIVA" elif TOTAL == 0: return "DIOT" elif TOTAL_CONTABLE == 0: return "CONTABLE" elif ASIA > 0: return "DIFER POSI" else: return "DIFERNEGVA"