End of Month Calculation

Alhamdan1995

I have a date column and I want to show that date as end of month. For example, if one date is 08/01/21, I am looking to show this as 08/31/21. Something similar to End Of Month function in Excel.

Thanks

JordanB

Hi @Alhamdan1995
,

You may want to consider trying the "Increment date" processor within a Prepare recipe. I've included a screenshot below demonstrating how it works. Note that you may make the changes in place or add an output column.

You may also find the tutorial on Filtering and Processing Dates helpful!

If that does not work for you, would you please provide more detailed information on your use case?

Thanks so much,

Jordan

Catalina

Hi @Alhamdan1995
,

You could use a prepare recipe with custom Python functions. An example of a custom Python function that calculates the end of month is below. The input for this is a column called line that contains the dates as Strings (format MM/DD/YYY).

import datetime

def process(row):
      
    current = datetime.datetime.strptime(row["line"],'%m/%d/%y')
    EndOfMonth = (datetime.datetime(current.year + int(current.month / 12), ((current.month % 12) + 1), 1) - datetime.timedelta(days=1))
    row["line"]= datetime.datetime.strftime(EndOfMonth,"%m/%d/%y")
    return row

Alhamdan1995

Thanks Jordan. This is helpful and will work for what I am looking for now as I have the same date. However, if I have different dates (i.e. 8/1/21 & 8/3/21). If i do the "increment date" here, the first date will be end of month but the second will shift to Sep. What's the solution here?

hemsharma82

@Alhamdan1995
were you able to figure this out? I am also in need of this solution. Please advise. Thanks

CoreyS

Hi @hemsharma82
and welcome to the Dataiku Community. Do either of the two accepted solutions here work for your use case? If not can you describe a little bit about how your use case may differ?

hemsharma82

@CoreyS
, thank you for responding. None of the two solutions are working for my use case. My goal is to calculate "Last Day of the Current Month" and "Last Day of the Previous Month". I have use now() function to get the "Current Date" and trying to calculate the above two values from "Current Date Column". I hope this clarifies the requirement. Best, Hem

Catalina

Hi @hemsharma82
,

We would like to know why the accepted solutions are not working for your use case. If you are getting any error messages, please share them.

Can you share also the Python code that you are using? Please confirm the input column type and date format.

Catalina

Hi @hemsharma82
,

Below is the Python code that calculates last day of the current month based on the current date returned by the now() function:

import datetime
   
current = datetime.datetime.now()
print(current)

EndOfMonth = (datetime.datetime(current.year + int(current.month / 12), ((current.month % 12) + 1), 1) - datetime.timedelta(days=1))
print(EndOfMonth)

The output of this code is:

2022-08-04 14:51:54.232576
2022-08-31 00:00:00

hemsharma82

Thank you Catalina. Where exactly in the recipe interface do I write this code?

CoreyS

Hi @hemsharma82
as mentioned in @CatalinaS
original solution, you can use a prepare recipe with custom Python functions. I hope this helps!

Ian

Hi @CatalinaS
,

Granted, my knowledge of Python is very limited. I have tried to use this code in a prepare recipe (both with and without the "def process(row):" and "return len(row)" that are inserted automatically) and keep getting errors.

chi_wong

if you don't want to use python, you can do it in a formula step

inc(concat(datePart(audt_start_dt_max,"year"),"-",mod(datePart(audt_start_dt_max,"Month"),12)+1,"-01"),-1,"day")

PrathameshPatil

This formula works perfectly until we are looking at December. A minor modification to to include December:
if(
datePart(audt_start_dt_max,"Month") == 12 ,
inc(concat(datePart(audt_start_dt_max,"year")+1,"-",mod(datePart(audt_start_dt_max,"Month"),12)+1,"-01"),-1,"day"),
inc(concat(datePart(audt_start_dt_max,"year"),"-",mod(datePart(audt_start_dt_max,"Month"),12)+1,"-01"),-1,"day")
)

GabrielBerno

This formula brings the last day of the month, is there a way that we could get the last working/business day of the month?

Catalina

Hi @GabrielBerno
,

You can get the last working day of the month using this custom Python function:

import datetime
from datetime import timedelta

def process(row):
    current = datetime.datetime.strptime(row["line"],'%m/%d/%y')
    EndOfMonth = (datetime.datetime(current.year + int(current.month / 12), ((current.month % 12) + 1), 1) - datetime.timedelta(days=1))
    if EndOfMonth.isoweekday() >5:
        EndOfMonth = EndOfMonth - datetime.timedelta(days=EndOfMonth.isoweekday()-5)
    row["EndWeek"]= datetime.datetime.strftime(EndOfMonth,"%m/%d/%y")
    return row

GabrielBerno

@CatalinaS
thanks very much, that works perfectly for the weekends but, besides the weekends, I would like to consider the holidays too. I tried the "Flag holidays" processor but it doesn't includes brazilian holidays, do you have any ideas that I could adopt?

PS: I'm from Brazil.

tgb417

@GabrielBerno
,

if you are comfortable with python recipes you might try using the python library https://pypi.org/project/holidays/

or if you can find or create a table of Brazilian holidays you could join this to your dataset.

just a couple of ideas. Let us know how you get on with this.

GabrielBerno

@tgb417
Thank you! I guess I will go with the table of Brazilian holidays option.